{
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  {
   "cell_type": "code",
   "execution_count": 13,
   "metadata": {},
   "outputs": [],
   "source": [
    "# Practice Problem 1\n",
    "# Write a function that returns the maximum of two numbers.\n",
    "#\n",
    "def max2(num1,num2):   # function header or function signature; contains NAME of function and a list of parameter NAMES    \n",
    "    if num1 > num2:\n",
    "        return num1\n",
    "    else:\n",
    "        return num2\n",
    "\n",
    "# What is a parameter?\n",
    "# it is a generic name to variable that is typically an INPUT to a function "
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 14,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "40\n",
      "35\n"
     ]
    }
   ],
   "source": [
    "print(max2(10,20))\n",
    "print(max2(30,5))"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 15,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "220"
      ]
     },
     "execution_count": 15,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "max2(100,200)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 25,
   "metadata": {},
   "outputs": [],
   "source": [
    "def nationality(name):\n",
    "    ???\n",
    "    ???\n",
    "\n",
    "\n",
    "def uselessFunction(name):\n",
    "    if nationality(name) == \"India\":\n",
    "        return \"Namaste\"\n",
    "    else:\n",
    "        return \"Hello\""
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 26,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "'Hello'"
      ]
     },
     "execution_count": 26,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "uselessFunction(\"\")"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 28,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "'Namaste'"
      ]
     },
     "execution_count": 28,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "uselessFunction(\"James\")"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 22,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Namaste\n",
      "Namaste\n",
      "Namaste\n",
      "Namaste\n",
      "Namaste\n",
      "Namaste\n",
      "Namaste\n",
      "Namaste\n",
      "Namaste\n",
      "Namaste\n"
     ]
    }
   ],
   "source": [
    "for i in range(10):\n",
    "    print(uselessFunction())"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 23,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Namaste\n"
     ]
    }
   ],
   "source": [
    "print(\"Namaste\")"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 29,
   "metadata": {},
   "outputs": [],
   "source": [
    "def square(n):\n",
    "    return n*n"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 37,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "True"
      ]
     },
     "execution_count": 37,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "square(10000000000000000000000000000) == 100000000000000000000000000000000000000000000000000000000"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "# FINITE DIGITAL COMPUTER\n",
    "# ANALOG COMPUTER\n",
    "# INIFINITE PRECISION ARITHMETIC"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 41,
   "metadata": {},
   "outputs": [],
   "source": [
    "# Problem 2\n",
    "# Write a function called fizz_buzz that takes a number as parameter. \n",
    "# If the number is divisible by 3, it should return “Fizz”. C1 \n",
    "# If it is divisible by 5, it should return “Buzz”. C2\n",
    "# If it is divisible by both 3 and 5, it should return “FizzBuzz”. C3\n",
    "# Otherwise, it should return the same number.\n",
    "\n",
    "# C3 implies C1 and C2\n",
    "def fizz_buzz(num):\n",
    "    if num%3 == 0 and num%5 == 0:\n",
    "        return \"FizzBuzz\"\n",
    "    elif num%3 == 0:\n",
    "        return \"Fizz\"\n",
    "    elif num%5 == 0:\n",
    "        return \"Buzz\"\n",
    "    else:\n",
    "        return str(num)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 45,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "'8'"
      ]
     },
     "execution_count": 45,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "fizz_buzz(8)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 39,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "0"
      ]
     },
     "execution_count": 39,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "9%3"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 48,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "1"
      ]
     },
     "execution_count": 48,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "13//3\n",
    "13%3"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": [
    "+, -, *, /, %, //, "
   ]
  }
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